The mass suspended from the stretched string of a sonometer is 2 kg and the frequency of the tuning fork used is 100 Hz. If the length of the string between the wedges is 50 cm, find the linear mass density of the string. (Taking g = 10 m s ^ –2).
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Answer:
Tension in the string = mg = 2 kg × 20 N
Frequency = 100 Hz
Length of string = 50 cm = 0.5 m
Fundamental frequency, n = 1/2 ×√T/√m
=> n^2 = T/4L^2 m
=> m = T/4l^2 n^2
Answered by
0
Answer:
Tension in the string = mg = 2 kg × 20 N
Frequency = 100 Hz
Length of string = 50 cm = 0.5 m
Fundamental frequency, n = 1/2 ×√T/√m
=> n^2 = T/4L^2 m
=> m = T/4l^2 n^2
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