Question

The mass suspended from the stretched string of a sonometer is 2 kg and the frequency of the tuning fork used is 100 Hz. If the length of the string between the wedges is 50 cm, find the linear mass density of the string. (Taking g = 10 m s ^ –2).​ Solve with explanation.​

Answer 1

Answer:

Tension in the string = mg = 2 kg × 20 N

Frequency = 100 Hz

Length of string = 50 cm = 0.5 m

Fundamental frequency, n = 1/2 ×√T/√m

=> n^2 = T/4L^2 m

=> m = T/4l^2 n^2

$\frac{20}{4 \times \frac{1}{4} \times {100}^{2} } = 2 \times 10 { }^{ - 3} kg \: m {}^{ - 1}$

Therefore, linear mass density of the string is

$2 \times 10 {}^{ - 3} kg \: m {}^{ - 1}$

Answer 2

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