The masses of three wires of copper are in the ratio 1: 3:5
and their lengths are in the ratio 5: 3: 1. The ratio of their
electrical resistances is
(a) 1:3:5
(b) 5:3:1
(c) 1:15: 125
(d) 125: 15:1
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Answer:
(d)125:15:1
Explanation:
When we speak of length and mass of a resistor then resistance becomes directly proportional to the square of the length and inversely proportional to the mass
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