Question

The masses of two bodies are in the ration3:4. on applying a certain force on the first body,an acceleration of 6m/s2 is produced what will be the acceleration in the second body when the Same force is applied on it

Answer 1

Given , Ratio of mass of two bodies = 3 : 4
Then, let mass of first body be m1 and second body be m2.
M1 = 3x
M2 = 4x
Acceleration of first body, = 6m/s^2
Given, Force, F1 = Force, F2
For first body, F = Mass * acceleration
F1 = 3x * 6 m/s^2
F2 = 4x * a 2 ( acceleration in the second body)
Since, F 1 = F 2
3x * 6 = 4x * a 2
18x / 4x = a2
a 2 = 4.5 m/s^2

Acceleration in the second BODY = 4. 5 m/s^2

Answer 2

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given:

F1=F2

acceleration of a body=6m s^-2

acceleration of second body=?



Let the mass of the body be 3x and 4x then,



Force =mass × acceleration

F1=3x×6

F1=18x

F2=4x× a

°•° F1=F2 then,

18x=4xa

4a=18

a=4.5m/s^2


hence acceleration of second body is 4.5m/s^2
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