Question

The maximum acceleration of S.H.M. is a and the maximum velocity is ß.
what amplitude of S.H.M. will be​

Answer 1

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Maximum acceleration = Aω² = α   ------(1)

Maximum velocity = Aω = β      ------(2)

Hence,

Aω²/Aω = α/β

ω = α/β

(1) + (2) =>

Aω( ω + 1 ) = α + β

Substituting ω = α/β

Aα/β (α/β + 1) = α + β

A = (α + β)β / α(α/β + 1)

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