Question

the maximum and minimum value of the function y=x^3 -3x^2+6r ?​

Answer 1

Answer::

y=9−(x−3)2=6x−x2

dydx=6−2x

For minimum or maximum value of y,

dydx=0

⇒6−2x=0⇒x=3

Here d2ydx2=−2 is less than zero at x=3.

ymax=9−(3−3)2=9

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Explanation: