The maximum distance of the centre of the ellipse from the chord of contact of mutually perpendicular tangents of the ellipse is
1)
12/5
2)
4/5
3)
32/5
4)
16/5
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ФФThe maximum distance of the centre of the ellipse from the chord of contact of mutually perpendicular tangents of the ellipse is
Answer:
16/5
Step-by-step explanation:
Perpendicular tangents meet on director circle x²+ y² =25
Equation of chord of contact of ellipse w.r.t this point is
5cosФ x/ 16 + 5sinФy/9 = 1
Distance from center = 1/√{25/256cos^{2} Ф +√25/81sin^{2}Ф
Maximum value cosФ = 1 and sin Ф = 0
Therefore the maximum distance is 16/5
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