The maximum friction force between the tyres of a car and the road is half the weight of the car .If the car negotiates a curve of radius 20m. Find the velocity of the car .(g=10m/s^2)
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Answer:
v = 14.2 m/s
Explanation:
centripetal force
F = mv²/r ..... (1)
F = mg ...... (2)
from equation 1 and 2 we get
mg = mv²/r
g = v²/r
v²=gr
v=√gr
v= √20×10
v = √200
v = 14.2 m/s
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