the maximum intensity in young's double slit experiment is I not the distance between two slits is 5 Lambda. find out the intensity of light in front of one of the slit on the screen at the distance of 10 d .
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d = 5 lemda
D = 10d = 10× 5 lemda = 50 lemda
y= d/2
= 5 lemda/2
the phase difference between two slits wave emitted by S1 and S2 ,
= Io cos^2(π/4)
= Io ×(1/√2)^2
= Io/ 2
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