Question

the maximum length of s pencil that can be kept in a rectangle box of dimensions 12cm*9cm*8cm is=​

Answer 1

Answer:

17 cm

Step-by-step explanation:

the maximum length of the pencil=

$\sqrt{ {12}^{2} + {9}^{2} + {8}^{2} } \\ = \sqrt{144 + 81 + 64 } \\ = \sqrt{289} \\ = 17 \: cm$

Answer 2

Answer:

17 cm

Step-by-step explanation:

the maximum length of the pencil is diagonal of cubiod is 17cm