Question

The maximum number of 40 W tube-lights connected in parallel which can safely be run from a 240 V supply with a 5 A fuse is :; A. 5; B. 15; C. 20; D. 30

Answer 1

Answer:

(D) 30

Explanation:

As per the question,

Given data:

Power of 1 tube light = 40 W

Voltage = 240 V

Current of fuse = 5 A

Let us consider the number of  tube-lights connected in parallel and can run safely be = N

Therefore,

Power of N tube light = 40 × N

Since we know that,

Power is defined as voltage multiplied by current,that is,

Power = voltage × current

⇒ 40N = 240 × 5

⇒ N = 30

Hence, the number of  tube-lights connected in parallel and can run safely = 30

Therefor, option (D) is correct.