Math, asked by krishnanmuruga740, 1 year ago

The maximum number of comparisons needed to sort 9 items using radix sort is (assume each item is 5 digit octal number) :

Answers

Answered by sherafgan354
6

Answer:

360

Step-by-step explanation:

Total items to sort = 9

Each item is octal and have 5 digits

now the worst case performance of radix sort or maximum number of comparisons of radix sort is O(wn)

here O=9

w=5 and n=8

so Maximum Number of iterations are = 9 * 5* 8

                                                                = 360

Answered by writersparadise
6

Answer:

360 maximum number of comparisons.

Step-by-step explanation:

An octal number is a type of number that is composed of 8 possible values (0 to 7). In the question, it is a five digit octal number. Now, comparisons required to sort any set of numbers can be maximised by applying the formula:


Maximum comparisons = (Digits) x (Type of Number) x (Number of values)

Maximum comparisons = 5 x 8 x 9 = 360

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