Question

The maximum range of a projectile fired with some initial velocity is found to be 1000 m in the absence of wind and air resistance. The maximum height reached by this projectile is

Answer 1

Answer:

The maximum height reached = 250 meter

Explanation:

The maximum range occurs when the angle of projection = 45 degree

$Range = \frac{u^2*sin(2*45)}{g} = \frac{u^2}{g} = 1000m$

$Maximum..height = \frac{u^2sin^245}{2g}=\frac{u^2}{2g} (\frac{1}{\sqrt{2} } )^2=\frac{u^2}{4g}=\frac{1000}{4}= 250m$

The maximum height reached = 250 meter