Question

The maximum resistance which can be made using four resistors each resistance 1/2Ω is

(a) 2 Ω
(b) 1Ω
(c) 2.5 Ω
(d) 8Ω​

Answer 1

Answer:

(a) 2 Ω

Explanation:

1/2Ω+1/2Ω+1/2Ω+1/2Ω=4/2=2

Answer 2

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Given :

• There are 4 resistors of 1/2Ω each

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To Find :

• Maximum Value of Current

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Solution :

The maximum amount of resistance is when, when all the resistors are connected in series and if we need minimum value of the resistance add all the resistors in parallel.

So, use formula for series,

$\Large \star {\boxed{\boxed{\sf{R_s \: = \: R_1 \: + \: R_2 \: + \: R_3 \: + \: R_4}}}}$

Where, R1 = R2 = R3 = R4 = 1/2 Ω

Put Values,

$\implies {\sf{R_s \: = \: \dfrac{1}{2} \: + \: \dfrac{1}{2} \: + \: \dfrac{1}{2} \: + \: \dfrac{1}{2}}} \\ \\ \implies {\sf{R_s \: = \: \dfrac{4}{2}}} \\ \\ \implies {\sf{R_s \: = \: 2}} \\ \\ \implies {\sf{R_s \: = \: 2 \: \Omega}} \\ \\ \\ {\underline{\sf{\therefore \: \: \: Maximum \: Resistance \: is \: 2 \: \Omega}}}$

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# Learn More

Derivation of

series combination of resistors

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