Question

The maximum speed of a train is 90 km/h. It takes 10 hours to cover a distance of 500 km. Find the

ratio of its average speed to maximum speed?​

Answer 1

$\Large{\colorbox{black}{\bf{Given : }}}$

> ᴍᴀxɪᴍᴜᴍ sᴘᴇᴇᴅ ᴏғ ᴛʜᴇ ᴛʀᴀɪɴ = 90km/h

> ᴛɪᴍᴇ ᴛᴀᴋᴇɴ = 10hours

> ᴅɪsᴛᴀɴᴄᴇ = 500 km.

$\Large{\colorbox{black}{\bf{To Find : }}} \:$

> Ratio of It's average speed to maximum speed.

$\Large{\colorbox{black}{\bf{Solution : }}} \: \:$

$\fbox{\Large{\sf{\purple{Avr.Speed = \frac{total \: \: distance}{total \: time \: taken}}}}}$

$\implies \Large{\sf{ \frac{500}{10}} } \\ \\ \implies \large{\fbox{50 \: km/hr}} \:$

NOW, Let's calculate the ratio :

$\implies\Large {\sf{\frac{Speed_{Avrg}}{Speed_{Max}} = \frac{50}{90}</p><p> \: }}$

$\implies \Large \colorbox{black} {\Large{\sf{5:9}}}$

Hence ., the ratio of Average speed to maximum speed = 5:9

$\huge\mathfrak\red{Solved} \:$

Answer 2

$\bf \Huge \implies\: Given :$

• Maximum Speed of train = 90 km/h

• Time = 10 hours

• Distance Covered = 500 km

_________________________________

$\bf \Huge \implies \: To \: \: Find :$

Ratio of its average speed to maximum speed?

_________________________________

$\bf \Huge \implies \: Solution :$

$\bf \small \rightarrow \: Average \: \: speed \: = \frac{Total \: \: Distance}{Total \: \: Time}$

$\bf \Large \iff \: \frac{500}{10} = 50 \: km/hour$

⇥ So , the average speed is 50 km / h .

$\bf \scriptsize \: Ratio \: \: of \: \: Maximum \: \: and \: \: Average \: \: speed \: \: is = \frac{90}{50}$

$\bf \Large \iff \: \frac{90}{50} = \frac{9}{5}$

$\bf \large \iff \: 9: 5$

Hence , the ratio of Maximum and Average speed is 9 : 5.