Question

The maximum stress that can be applied to the material of a wire employed to suspend an elevator is 3/π × 10^8N/m^2
If the mass of the elevator is 900 kg and it moves up with an acceleration of 2.2 m/s2 then calculate the minimum
radius of the wire.​

Answer 1

Answer:

S

max

=

π

3

×10

8

N/m

2

m=900kg

ma=T−mg

900×2.2=S

m

×A−900×10

S

m

.A=900×12.2

A

max

=

π

3

×10

8

900×12.2

πr

min

2

=

π

3

×10

8

900×12.2

r

min

2

=12.2×3×10

−6

r

min

=6×10

−3

r

min

=6mm