Question

the maximum torque experienced by a bar magnet placed in a uniform magnetic field is 7×10^-4 nm. if the magnet makes an angle of 60° with the field direction, the potential energy of the system is​

Answer 1

Answer:

Torque = M×B

.·. (M)(B)= (14/√3)×10^-4Nm

potential energy is given by

U= -MBsin∅