The maximum velocity if a simple harmonic oscillator represnted by y=3sin(100t+pi/6)is
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Answer:
300ms−1
Explanation:
The given equation is written as
y=3sin(100t+π6).. (i)
The general equation of simple harmonic motion is written as
y=asin(ωt+ϕ)... (ii)
Equating Eqs. (i) and (ii), we get
a=3,ω=100
Maximum veiocity, v = aω
3×100
=300ms−1
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