Question

The maximum velocity of photoelectrons emitted from a metal surface is 1.76 106 ms1. If the e/m ratio of an electron is 1.76 1011 c kg 1, then the stopping potential of the metal (in v) is

Answer 1

The stopping potential is  8.8 V

Explanation:

Given data:

Velocity of photo electrons = 1.76 x 10^6 m/s

Specific charge f electron = 1.76 x 10^11 C / Kg

1 / 2mv^2(max) = eV's

Vs = mv^2 max / 2e

Vs =  (1.76 x 10^6)^2 / 2 x 1.76 x 10^11

Vs = 3.0976 x 10^12 / 3.52 x 10^11

Vs = 0.88 x 10 = 8.8 V

Hence the stopping potential is  8.8 V

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