Question

The maximum vertical height of a projectile in 10 m
if the magnitude of the initial velocity in 28 ms.
what is the direction of the initial velocity ? Take
= 9.8 ms​

Answer 1

The maximum height of a projective is achieved when all of its vertical (kinetic) energy is converted into gravitational potential energy.

So,mgh = 1/2 mv 2/y

This will give you the value of the vertical component of velocity.The resultant of this component and horizontal component is the initial velocity. So,

v=root vx^2+root v^2y

Finally,the angle that the initial velocity makes with the ground can be found out as a teregonometric functions of the ratio of the velocity components.

O=tan^-1(vy/vx)

At the end of all this calculations,you are left with

vy=root 20 g

vx=2 root 196 - root 5g

O=tan^-1(root 20 g/2 root 196 - root 5g=30°

thnks:)

Answer 2

Answer:

The maximum vertical height of a projectile is 10 m. If the magnitude of the initial velocity is 28 m/s,

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