Question

The mean age of two populations A and B of sizes 50 and 100 respectively are 54.1 and

50.3 years and their standard deviations are 8 and 7 years. Which of the two

populations has greater variability in age? Is it possible to conclude that population A is

older than population B?​

Answer 1

Answer:

Step-by-step explanation:

The mean age of two populations A and B

Mean of A of sizes 50=  54.1

Mean of B of sizes 100 =  50.3 years

 Standard deviations of A =  8 years

Standard deviations of B =  7 years.

Arithmetic mean X bar = ∑ x / N

= Sum of the data given / Number of data

Mean of A of sizes 50

Arithmetic mean X bar = ∑ x / N

54.1 = ∑x / 50

54.1 × 50 = ∑x

2705 = ∑x

Mean of B of sizes 100

Arithmetic mean X bar = ∑ x / N

50.3 = ∑x / 100

50.3 × 100 = ∑x

5030  = ∑x

Population of B is more or greater variability in age.