Question

The mean and median of a distribution are 14 and 15 respetively. The
value of mode is​

Answer 1

Answer:

use the emperical formula :- mode =3median -2mean

Step-by-step explanation:

3(15) -2(14) =mode

=45-28

= 17

Answer 2

$\bf \red{mean =14 } \\ \bf \pink{median = 15} \\ \bf \orange{mode = ?}$

$\large \sf \gray{we \: know \: that } \: \sf{mode} \: \sf \gray{ = 3median - 2mean}$

$\frak \gray{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:= 3(15) - 2(14)} \\ \frak \gray{ \: \: \: \: \: \: \: \: \: \: = 45 - 28} \\ \frak \gray{ = 17}$

Hence,the value of mode is 17.