the mean and standard deviation of 100 observation are 40 and 5.1 respectively.it was later found that one observation was wrongly copied as 50 in place of 40 . find the correct mean and standard deviation?
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the mean of 100 observations = 40
sum of the observations = 4000
it was observed that 50 is written in place of 40
sum of the correct observations = 4000-50+40
= 4000-10 =3900
correct mean = 3900/100 =39
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