The mean of 5 no.s is 18 if one no. Is excluded the mean is 16 find the xclyded no.
Answers
Answered by
4
(y+x)/5=18
y+x=90 eq(I)
y/4=16
y=64 eq(2)
subtracting eq1 and eq 2
x=26 (Ans)
y+x=90 eq(I)
y/4=16
y=64 eq(2)
subtracting eq1 and eq 2
x=26 (Ans)
Answered by
3
hi friend,
let p,q,r,s,t be 5 numbers
<>mean of 5 numbers is 18
→p+q+r+s+t/5=18
→p+q+r+s+t=90----(1)
let 't' be removed,
then mean of 4 numbers is 16
→p+q+r+s/4=16
→p+q+r+s=64----(2)
now, t=(1)-(2)
=90-64=26
I hope this will help u ;)
let p,q,r,s,t be 5 numbers
<>mean of 5 numbers is 18
→p+q+r+s+t/5=18
→p+q+r+s+t=90----(1)
let 't' be removed,
then mean of 4 numbers is 16
→p+q+r+s/4=16
→p+q+r+s=64----(2)
now, t=(1)-(2)
=90-64=26
I hope this will help u ;)
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