Question

The mean of 5 numbers is 18. If one number is excluded , their mean is 16. Find the excluded number.

Answer 1

Answer:

mean of 5 numbers is 18

(a1+a2+a3+a4+a5) /5=18

sum of all numbers will be 90{5×18}

let a1 be the excluded number

(a1+a2+a3+a4+a5)=90

a2+a3+a4+a5=90-a1

so,

a2+a3+a4+a5/4=16

90-a1=64

a1=26

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Answer 2

Step-by-step explanation:

normal method ::

let the sum of no.s be S1

mean=sum /no.of elements

according to sum

18=S1/5

S1=90

Note:this S1 contains that excluded no. also

when 1 no. is excluded then sum be S2

therefore 4 elements are there

S2=16×4

S2=64

excluded no.is S1-S2

90-64=26

short cut:;

5. 18

4. 16

18-16=2

2×4=8

18+8=26

it's exclusively a correct method

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