The mean of 5 observation is 10 . If mean of first three observations and that of last three is 11 , find third observation .
I am a student of class 7
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Answer:
16
Step-by-step explanation:
Mean = sum of observations / no. of observations
Let the observations are a , b , c , d and e.
According to question :
⇒ mean of all = 10
⇒ ( a + b + c + d + e ) / 5 = 10
⇒ a + b + c + d + e = 5 * 10
⇒ a + b + c + d + e = 50 ...( 1 )
Mean of 1st 3 is 11 :
⇒ ( a + b + c ) / 3 = 11
⇒ a + b + c = 3 * 11 = 33 ...( 2 )
Mean of last 3 is 11
⇒ ( c + d + e ) / 3 = 11
⇒ c + d + e = 3 * 11 = 33 ...( 3 )
Adding ( 2 ) and ( 3 ):
⇒ ( a + b + c ) + ( c + d + e ) = 33 + 33
⇒ a + b + c + c + d + e = 66
⇒ a + b + c + d + e + c = 66
value of a + b + c + d + e from ( 1 )
⇒ 50 + c = 66
⇒ c = 66 - 50
⇒ c = 16
⇒ third observation = c = 16
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