Question

The mean of a b c d and e is 28 if the mean a c and e is 24 what is the mean of B and d

Answer 1

The mean of a b c d and e is 28
sum=a+b+c+d+e= 28×5 = 140

the mean a c and e is 24
a+c+e=24×3 = 72

b+d = 140 -72 = 68
mean of b and d = 68/2= 34

Answer 2

Answer:

$mean \: of \: b \: and \: d = 34$

Step-by-step explanation:

Given mean of a,b,c,d and e is 28.

$\boxed { mean = \frac{sum \:of \: the \: terms}{number \:of \:terms }}$

$\frac{a+b+c+d+e}{5}=28$

$\implies a+b+c+d+e = 28\times 5$

$\implies a+b+c+d+e = 140---(1)$

$mean \:of\:a, \: c\: and \: e = 24$

$\implies a+c+e = 3\times 24$

$\implies a+c+e = 72---(2)$

Subtract equation (2) From (1) , we get

$\implies b+d = 68$

Divide both sides by 2 ,we get

$\implies \frac{b+d}{2}=\frac{68}{2}$

$\implies mean \: of \: b \: and \: d = 34$

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