The mean of a set of 20 observation is 19.3. The mean is reduced by 0.5 when new observation is added to the set .find the new mean.class inter.0-5........20-25.freq.10,15,12,20,9
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Solution :-
Two questions are given but only the first one is clear. So, I have solved the first question only.
Given -
Mean of 20 observations = 19.3
Mean = Sum of observations/Total number of observations
⇒ 19.3 = Sum of 20 observations/20
⇒ Sum of 20 observations = 20*19.3
Sum of 20 observations = 386
When a new observation is added then the new mean decreases by 0.5
Then,
Mean of 21 observations = Sum of 21 observations/21
⇒ 19.3 - 0.5 = Sum of 20 observations + 21st observation/21
⇒ 18.8 = 386 + 21st observation/21
⇒ 386 + 21st observation = 18.8*21
⇒ 386 + 21st observation = 394.8
⇒ 21st observation = 394.8 - 386
⇒ 21st observation = 8.8
So, 21st observation is 8.8
New mean = 394.8/21
New Mean = 18.8
Answer.
Two questions are given but only the first one is clear. So, I have solved the first question only.
Given -
Mean of 20 observations = 19.3
Mean = Sum of observations/Total number of observations
⇒ 19.3 = Sum of 20 observations/20
⇒ Sum of 20 observations = 20*19.3
Sum of 20 observations = 386
When a new observation is added then the new mean decreases by 0.5
Then,
Mean of 21 observations = Sum of 21 observations/21
⇒ 19.3 - 0.5 = Sum of 20 observations + 21st observation/21
⇒ 18.8 = 386 + 21st observation/21
⇒ 386 + 21st observation = 18.8*21
⇒ 386 + 21st observation = 394.8
⇒ 21st observation = 394.8 - 386
⇒ 21st observation = 8.8
So, 21st observation is 8.8
New mean = 394.8/21
New Mean = 18.8
Answer.
Mayank9432:
thank you
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