The mean of distribution of 50 determine the value of g 3
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Means is given as 50
⇒
1
∑
5
f
1
∑
5
xf
=50
⇒
17+5a+3+32+7a−11+19
170+150a+90+1600+490a−770+1710
=50
⇒640a+2800=3000+600a
⇒40a=200
⇒a=5
Hence, option C.
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