the mean of first n natural numbers is X what is the mean of first n even number even natural numbers
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first n natural numbers are ; 1, 2, 3, 4, ..... n
we know, mean = sum of observations/total number of observations
X = (1 + 2 + 3 + 4 + ... + n)/n
X = {n(n + 1)/2}/n
X = (n + 1)/2 ........(1)
[ note : sum of n natural numbers = n(n + 1)/2]
again, first n even natural numbers ; 2, 4, 6, 8, .... n
sum of first n even natural number = 2 + 4 + 6 + 8 + .... + n terms
it is an arithmetic progression,
so, using formula, S = n/2 [a + tn]
here, tn = a + (n - 1)d
= 2 + (n - 1)2 = 2n
now, sum of first n even natural numbers = n/2 [2 + 2n] = n(n + 1)
so, mean of first n even natural numbers = n(n + 1)/n = (n + 1)
from equation (1),
mean of first n even natural numbers = 2X
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