Question

the mean of first 'n' positive odd integers is equal to:
a) 2n - 1
b)2n
c)n
d)2n+1/2​

Answer 1

Answer:

mean of first 'n' +eve odd integers = n

Explanation

sum of first n odd numbers,

ie., 1+3+5+...n terms = n²

so, the mean = sum/no. of terms

                      = n²/n

                      = n

Answer 2

Answer:

Range of first 'n' positive odd integers = (2n + 1) - (1) = 2n -2 .

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