Question

The mean of five numbers is 40. If one number is included , then their mean becomes 38. Find the excluded number.

Answer 1

Mean of five numbers = 40
total value of five numbers = 40×5 = 200
if one number number is included then
Mean of six numbers = 38
so,total value of six numbers = 38×6= 228

therefore, excluded number = 228- 200= 28

I hope it will help you

Please mark as brainliest

Answer 2

The excluded number is 48

Step-by-step explanation:

$Average = \frac{\text{Sum of all observations}}{\text{No. of observations}}$

The mean of five numbers is 40.

$40 = \frac{\text{Sum of 5 numbers}}{5}$

$40 \times 5 = \text{Sum of 5 numbers}$

$200= \text{Sum of 5 numbers}$

Let the excluded number be x

So, new sum = 200-x

No. of observations = 5-1=4

If one number is excluded then their mean becomes 38.

$38=\frac{200-x}{4}$

$38 \times 4 = 200-x$

$152=200-x$

$x=200-152$

x=48

Hence The excluded number is 48

#Learn more:

The mean of five numbers is 18.on excluding one number ,the mean becomes 16.find the excluded number.

https://brainly.in/question/2382068