Question

the mean of sino°,cos30°,tan45°,cot60°​

Answer 1

Step-by-step explanation:

$\sin(0) = 0 \\ \cos(30) = \frac{ \sqrt{3} }{2} \\ \tan(45) = 1 \\ \cot(60) = \frac{1}{ \sqrt{3} }$

Answer 2

Step-by-step explanation:

Sin 0degree=0

cos30 degree=root 3 by 2

tan45 degree=1

and

cot60 degree=1 by root 3