the mean of the following frequency distribution is 50 The frequencies F1 and F2 in the class 20 to 40 and 60 to 80 are missing find the missing frequency using step deviation method
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∑fi = f1+f2 = 52
Mean = ∑fiui/∑fi
6000-3480 = 30f1+70f2
f2 = 2520-30f1/70
∴ putting value of f2
f1 + 2520-30f1/70 = 52
40f1 + 2520 = 3640
f1 = 1120/40
f1 = 21
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the F1 is equals to 28 and F2 is equals to 24
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