Question

the mean of the following frequency why distrubition is 20 qetermine ttyl​

Answer 1

${\huge{\sf {\orange{\underline{Answer}}}}}$

$\: \:$

$i. \: \frac{1}{10}$

$ii. \: \frac{3}{10 }$

$iii. \: \frac{3}{5}$

$\: \:$

${\huge{\sf {\orange{\underline{Explanation :}}}}}$

$\: \:$

Total number of cards in a deck = 52

No. of cards removed = 12

No. of cards left = 52 - 12 = 40

$\: \:$

$probability \: = \: \frac{no. \: of \: favourable \: outcomes}{total \: no. \: of \: outcomes}$

$\: \:$

${\large{\sf {\green{\underline{Part 1}}}}}$

$\: \:$

No of cards with value 7 = 4

[ Cards with no. 7 from all four groups ]

$\: \:$

$probability \: = \: \frac{no. \: of \: favourable \: outcomes}{total \: no. \: of \: outcomes}$

$probability \: = \: \frac{4}{40}$

$probability \: = \: \frac{1}{10}$

$\: \:$

${\large{\sf {\green{\underline{Part 2}}}}}$

$\: \:$

No. of cards greater than 7 = (3 × 4) = 12

[ Cards with numbers 8, 9, 10 from all four groups]

$\: \:$

$probability \: = \: \frac{no. \: of \: favourable \: outcomes}{total \: no. \: of \: outcomes}$

$probability \: = \: \frac{12}{40}$

$probability \: = \: \frac{3}{10}$

$\: \:$

${\large{\sf {\green{\underline{Part 3}}}}}$

No. of cards less than 7 = ( 6 × 4 ) = 24

[ Cards numbered from 1 to 6 from all four groups ]

$\: \:$

$probability \: = \: \frac{no. \: of \: favourable \: outcomes}{total \: no. \: of \: outcomes}$

$probability \: = \: \frac{24}{40}$

$probability \: = \: \frac{3}{5}$