The mean of the series a,a+nd,\,\,a+2nd
is [DCE 2002]
A) a+(n-1)\,d B) a+nd C) a+(n+1)\,d D) None of these
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Hi ,
a , a + nd , a + 2nd is given series ,
mean = ( sum of the terms )/number of terms
= ( a + a + nd + a + 2nd )/3
= ( 3a + 3nd )/3
= [ 3 ( a + nd ) /3 ]
= a + nd
Therefore ,
Option ( B ) is correct.
I hope this helps you.
: )
a , a + nd , a + 2nd is given series ,
mean = ( sum of the terms )/number of terms
= ( a + a + nd + a + 2nd )/3
= ( 3a + 3nd )/3
= [ 3 ( a + nd ) /3 ]
= a + nd
Therefore ,
Option ( B ) is correct.
I hope this helps you.
: )
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