Question

The mean of three numbers is 40. All the three numbers are different natural
numbers. If lowest is 19, what could be highest possible number of remaining two
numbers?
who answer correctly will be marked as brainllist​

Answer 1

ANSWER
Let the highest number be y and the middle number be x.
We know that,
Mean=
number of observations
sum of observations
​

∴ Mean=
3
x+y+z
​


Given that, Mean =40 and the lowest number =19.

∴40=
3
x+y+19
​

⇒x+y+19=120
⇒ x+y=120−19=101
⇒ y=101−x