The mean of three numbers is 40. All the three numbers are different natural numbers. If lowest is 19, what coould be the highest possible number of remaining twonumbers.
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total is 40*3 =120
lowest 19
remain 120-19=111
let the number s are X and y
remain sum 111/2=55.5
x+y=111
lowest 19
remain 120-19=111
let the number s are X and y
remain sum 111/2=55.5
x+y=111
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