Question

The mean of x,x+3,x+6 ,x+9, and x+12 is 10 then find x *
a)1
b)2
c)6
d)4​

Answer 1

$mean \: = \frac{x + x + 3 + x + 6 + x + 9 + x + 12}{5}$

$10 = \frac{5x + 30}{5}$

$5x + 30 = 50$

$5x = 50 - 30$

$x = \frac{20}{5}$

$x = 4$

Answer 2

|| ★.Solution.★ ||

The mean of x,x+3,x+6 ,x+9, and x+12 is 10

The mean of x,x+3,x+6 ,x+9, and x+12 is 10

↪ [ (x)+(x+3)+(x+6)+(x+9)+(x+12)]/5 = 10

↪ 5x + 30 = 10 × 5

↪ 5x = 50 - 30

↪ 5x = 20

↪ x = 20/5

↪ x = 4

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Verification Of Answer

The mean of x,x+3,x+6 ,x+9, and x+12 is 10

( Keep value of x )

↪ [ (4)+(4+3)+(4+6)+(4+9)+(4+12)]/5 = 10

↪ [ 20 + 30 ]/5 = 10

↪ 50 = 5 × 10

↪ 50 = 50

↪ L.H.S. = R.H.S.

That's proved.

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