Physics, asked by sharmasomya236, 1 year ago

The mean value of current for half cycle for a current variation shown by the graph is
Any graph take?

Answers

Answered by ChiragMeher
2
The process used to find the Average Voltageof an alternating waveform is very similar to that for finding its RMS value, the difference this time is that the instantaneous values are not squared and we do not find the square root of the summed mean.

The average voltage (or current) of a periodic waveform whether it is a sine wave, square wave or triangular waveform is defined as: “the quotient of the area under the waveform with respect to time”. In other words, the averaging of all the instantaneous values along time axis with time being one full period, (T).

For a periodic waveform, the area above the horizontal axis is positive while the area below the horizontal axis is negative. The result is that the average or mean value of a symmetrical alternating quantity is therefore zero, (0) because the area above the horizontal axis (the positive half cycle) is the same as the area below the axis (the negative half cycle) and thus cancel each other out. This is because when we do the maths of the two areas, the negative area cancels out the positive area producing zero average voltage.

Then the average or mean value of a symmetrical alternating quantity, such as a sine wave, is the average value measured over only one half of a cycle, since as we have just stated, the average value over one complete cycle is zero regardless of the peak amplitude.

The electrical terms Average Voltage and Mean Voltage or or even average current, can be used in both an AC and DC circuit analysis or calculations. The symbols used for representing an average value are defined as: VAV or IAV.


ParikshitMehta: copy paste
ParikshitMehta: from net
ParikshitMehta: from net
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