The measure if all the angles of a parallelogram if an angle is 24 kess than twice the smallest angle is
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First of all as parallelogram is a quadrilateral with opposite sides parallel so we can say the opposite angles are also parallel that is a parallelogram consist of two pair with same angle.
Now let x be the smallest angle of the parallelogram, Also as explained above there must be another angle equal to x as it is a parallelogram.
we remaining with two angles.
Now also it is given that the other angle is 24° less than twice of the smallest.
So we get angle to be
2x-24°
And same as x there must be another angle equal to 2x-24°
And as sum of all the angles of quadrilateral is 360°.
So adding all and euating with 360°.
2x-24+2x-24+x+x=360
6x=360+48
6x=408
x=68°
So the largest angle from here can be deduced
2*68–24
Which comes to be 112°.
If you still face some problem understanding it let me know, I'll upload a picture for more clarification.
Now let x be the smallest angle of the parallelogram, Also as explained above there must be another angle equal to x as it is a parallelogram.
we remaining with two angles.
Now also it is given that the other angle is 24° less than twice of the smallest.
So we get angle to be
2x-24°
And same as x there must be another angle equal to 2x-24°
And as sum of all the angles of quadrilateral is 360°.
So adding all and euating with 360°.
2x-24+2x-24+x+x=360
6x=360+48
6x=408
x=68°
So the largest angle from here can be deduced
2*68–24
Which comes to be 112°.
If you still face some problem understanding it let me know, I'll upload a picture for more clarification.
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