The measure ilof the anglesof a pentagon are(x-5),(x-6),(2x-7),xand(2x-2). Find the value of x
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Therefore,X is 80°.
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first we have to know the value of pentagon
angle of pentagon= (n-2)*180 here n represents number of sides
angle=(5-2)*180=3*180=540°
total angle = 540°
(x-5)+(x-6)+(2x-7)+x+(2x-2)=540°
7x-20=540
7x=560
x=80°
then measure of each angle is
1st angle (x-5)=80-5=75°
2nd angle (x-6)=80-6=74°
3rd angle (2x-7)= 2*80-7=160-7=153°
4th angle x =80°
fifth angle (2x-2)=2*80-2=160-2=158°
angle of pentagon= (n-2)*180 here n represents number of sides
angle=(5-2)*180=3*180=540°
total angle = 540°
(x-5)+(x-6)+(2x-7)+x+(2x-2)=540°
7x-20=540
7x=560
x=80°
then measure of each angle is
1st angle (x-5)=80-5=75°
2nd angle (x-6)=80-6=74°
3rd angle (2x-7)= 2*80-7=160-7=153°
4th angle x =80°
fifth angle (2x-2)=2*80-2=160-2=158°
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