The measure of all the angles of a quadrilateral PQRS are respectively in the ratio 7 : 9 : 11 : 13. What is the measure of the second largest angle?
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Answered by
21
Answer:
Let 7x,11x,13x be the these angles of a quadrilateral
Given 4th angle = 112∘
By angle sum property,
7x+11x+13x+112∘=360∘
31x=360∘−112∘=248∘
x=31248∘=8∘
∴7x=7×8∘=56∘11x=11×8∘=88∘
13x=13×8=104∘
Largets angle = 112∘
smallest angle = 56∘
Difference = 112∘−56∘=56∘
Answered by
1
Answer:
7x+9x+11x+13x=360
40x=360
x=360/40
x=9
11x=11(9)
=99
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