The measure of an angle if seven times its complement is 10 less than three times its supplement is
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Answered by
13
Let the angle be x
measure of its complement = (90-x)
measure of its supplement= (180-x)
7(90-x) =3(180-x)-10
630 - 7x=540x-3x -10
-7x+3x= 530-630
-4x=-100
x= 100/4
x=25
measure of its complement = (90-x)
measure of its supplement= (180-x)
7(90-x) =3(180-x)-10
630 - 7x=540x-3x -10
-7x+3x= 530-630
-4x=-100
x= 100/4
x=25
Answered by
0
Answer:
Let the complement angles = ( 90-x )
Let the supplement angles = ( 180- x )
According to Question,
7 ( 90-x ) = 3 ( 180-x ) -10
7×90 - 7× x = 3×180 - 3× x - 10
630 -7x = 540 - 10 -3x
-7x + 3x = 530 - 630
-4x = -100
x = 100÷4
x =25
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