Math, asked by katnissestella, 3 days ago

The measure of angle A is 16° greater than the measure of angle B. The two angles are complementary. Find the measure of each angle.

Answers

Answered by prachibarapatre
1

Answer:

The measure of ∠A and ∠B will be 53° and 37° respectively

Step-by-step explanation:

Here it is given that the measure of angle A is 6° greater than the measure of angle B.

Also, the two angles are complementary

We have to find both the angles

∠A = ∠B + 16

∠A + ∠B = 90

∠B + 16 + ∠B = 90

         2∠B + 16 = 90

                   2∠B = 74

                    ∠B = 74/2

                    ∠B = 37

So, ∠A = ∠B + 16

            = 37 + 16

            = 53

Answered by ajajit9217
1

Answer:

∠A is 53° and ∠B is 37°

Step-by-step explanation:

Let the measure of ∠B be x°

∴ The measure of ∠A =x° +16°     (as ∠A is 16° greater than ∠B)

We know that ,

the sum of complementary angle = 90°

∠A + ∠B = 90°

(x° + 16°) + x° = 90°

2x°  = 90° - 16°

  x° = 74°/2

  x° = 37°

∠ B = 37°

∠A = 37° + 16°

      =53°

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