Question

the measure of angle BCD in given figure is.....................
in above figure answer please​

Answer 1

$ABCD \:is \: a \:Cyclic \: Quadrilateral .[/tex</p><p>[tex] Given \: \angle {BAC} = 30\degree \: --(1)$

$\angle {CBD} = 70\degree \: --(2)$

$\angle {CAD} = \angle {CBD} = 70\degree$

$\blue {( Angles \:in \:the \:same \: segment \:are \: equal )}$

$Now, \angle {BAD} + \angle {BCD} = 180\degree$

/* The pair of opposite angles of a cyclic Quadrilateral are supplementary */

$\implies ( \angle {BAC} + \angle {CAD} )+ \angle {BCD} = 180\degree$

$\implies 30\degree + 70\degree + \angle {BCD} = 180\degree$

$\implies 100\degree + \angle {BCD} = 180\degree$

$\implies \angle {BCD} = 180\degree - 100\degree$

$\implies \angle {BCD} = 80\degree$

Therefore.,

$\red {\angle {BCD}}\green { = 80\degree}$

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Answer 2

Answer:

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