Question

The measure of each exterior angle of a hexagon is (3x – 4)°, (x + 4)°, (7x – 3)°, (8x – 1)°, (2x + 3)°,
(9x + 1)°. Find the measure of each angle.

Answer 1

We know that in any polygon sum of exterior angles is always 360°

So,

(3x – 4)° + (x + 4)° + (7x – 3)° + (8x – 1)° + (2x + 3)° + (9x + 1)° = 360°

=> (3x + x + 7x + 8x + 2x + 9x) + (- 4 + 4 - 3 - 1 + 3 + 1) = 360°

=> 30x + 0 = 360°

=> x = 360°/30

=> x = 12 °

So,

= (3x - 4)° = 32°
= (x + 4)° = 16°
= (7x - 3)° = 81°
= (8x - 1)° = 95°
= (2x + 3)° = 27°
= (9x + 1)° = 109°

Hope it helps !!!

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Regards,
AritraK • Expert •

Answer 2

Answer:

3x-4+x+4+7x-3+8x-1+2x+3+9x+1=360°

30x+0=360°

x=12

so,

the angles are:

(3x-4)=32°

(x+4)=16°

so on.......

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