The measure of four angles of a quadrilateral are (2x+10)°,(3x+15)°,(4x-30)°and (2x-20)° respectively;then find the measure of the smallest exterior angle of it? 1) 60° 2) 120° 3) 100° 4) 80°
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(2x+10)°+(3x+15)°+(4x-30)+(2x-20) = 360
2x+3x+4x+2x+10+15-30-20=360
5x+6x+10+15-30-20=360
11x-25=360
11x=360+25= 385
x=385/11= 35
(2x+10)= 2×35+10=80
(3x+15)=3×35+15=120
(4x-30)= 4×35-30=110
(2x-20)= 2×35-20=50
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