Question

the measure of one angle is 12 degree more than half the measure of its compliment, find measures of two angles?

Answer 1

• 1st angle = 38°
• 2nd angle = 52°

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$\orange{\bigstar}$  Given  $\green{\bigstar}$

1 . The measure of one angle is 12 degree more than half the measure of its compliment

$\orange{\bigstar}$  To Find  $\green{\bigstar}$

Two angles

$\orange{\bigstar}$  Solution  $\green{\bigstar}$

Let 1st angle be , " x "

So , Complementary angle be ,

" ( 90 - x ) "

From condition 1 ,

⇒ x = ( 90 - x ) / 2 + 12

⇒ 2x = 90- x + 24

⇒ 2x + x = 90 + 24

⇒ 3x = 114

⇒ x = 38  $\pink{\bigstar}$

So ,

1st angle , x = 38°  $\pink{\bigstar}$

2nd angle , ( 90 - x ) = 52°  $\pink{\bigstar}$

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Answer 2

$\huge{ \underline{\underline{\mathrm{ \red{Question}}}}}$

the measure of one angle is 12 degree more than half the measure of its compliment, find measures of two angles

$\huge{ \underline{\underline{\mathrm{ \red{Answer}}}}}$

${ \sf{ \underline{let \: us \: consider \: : - }}}$

• Angle: x

• Complement: 90-x

$\large{ \underline{ \sf{solution \: : - }}}$

$\sf \: Equation:$

• x = ( 90 - x ) / 2 + 12

• 2x = 90- x + 24

• 2x + x = 90 + 24

• 3x = 114°

➺x = 52°

➺90-x = 38°