The measure of one angle of a parallelogram is 50⁰ . Find the measures of the remaining three angles .
Give me a proper answer
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give me a proper answer
Answers
Given :-
- Measure of one angle of a parallelogram is 50°
To Find :-
- Measure of the remaining three angles
Solution :-
❒ Here , Let ABCD be a parallelogram whose one angle ( let it be ∠A ) is of 50° , and we know that opposite angles of a parallelogram are equal and in this parallelogram
★ ∠A = ∠C
★ ∠B = ∠D
➼ As , ( ∠A = ∠C ) and we're given the value of ∠A which is of 50°
then , ∠C is also equal to 50°
❒ Here , ABCD is also a quadrilateral and we know that , sum of all angles of a quadrilateral is 360° .
~Let measure of angle ∠B and ∠D be x° ( they are equal )
★ ∠A + ∠B + ∠C + ∠D = 360°
( putting value of ∠A and ∠C as 50° and ∠B and ∠D as x° )
→ 50° + 50° + x° + x° = 360°
→ 100° + 2x° = 360°
→ 2x = 360° - 100°
→ 2x = 260°
→ x = 260° ÷ 2
→ x = 130°
∴ ∠ A and ∠C = 50°
∠B and ∠D = 130°
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Question:-
The measure of one angle of a parallelogram is 50°. Find the measures of the remaining three angles.
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Given:-
- Measure of one angle of a parallelogram is 50°.
To Find:-
- The measures of the remaining three angles.
Diagram:-
Solution:-
We know that
In a parallelogram opposite angles are equal opposite are parallel.Thus two angles on the same side are supplementary.
So,The ∠A is 50° so the ∠C will also equal to 50°.
Let the other two angles be x.
Hence,
∠A and ∠C = 50°
∠B and ∠D = 130°
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[Note : Kindly see the above diagram in web browser.(Brainly.in)
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